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Table 3 Mediation analyses displaying associations between policy implementation (2017 vs. 2016), advertising exposure, and consumption of overall high-in foods (n = 679; 1,358 observations)

From: TV advertising and dietary intake in adolescents: a pre- and post- study of Chile’s Food Marketing Policy

 

a-coefficient2

b-coefficient

c’-coefficient

Direct Effect

ab

Indirect (mediation) Effect

Proportion of total variance accounted for by ab path 5

 

(policy→ ads)

(ads→ intake)

(policy→ intake)

 

β3

(99 % CI)

β

(99 % CI)

β

(99 % CI)

β

(99 % CI)

Absolute quantity (kcal)1,3

         

Any “High-in” ad

-4.6*

(-5.7, -3.5)

4

(-2, 10)

-37

(-135, 61)

-16

(-44, 12)

30.4 %

High calorie

-2.3*

(-2.8, -1.8)

8

(-6, 22)

-35

(-134, 64)

-18

(-50, 14)

34.2 %

High sugar

-3.0*

(-3.7, -2.3)

5

(-5, 14)

-39

(-137, 59)

-14

(-42, 15)

26.1 %

High fat

-1.3*

(-1.6, -1.0)

16

(-14, 46)

-32

(-133, 70)

-21

(-61, 18)

39.9 %

High sodium

-0.2*

(-0.3, 0.0)

31

(-18, 79)

-48

(-142, 46)

-5

(-14, 4)

9.4 %

Energy adjusted (% kcal)1,4

         

Any “High-in” ad

-4.6*

(-5.7, -3.5)

0.0

(-0.2, 0.3)

-3.6

(-7.4, 0.3)

-0.1

(-1.2, 1.0)

3.0 %

High calorie

-2.3*

(-2.8, -1.8)

0.1

(-0.5, 0.6)

-3.5

(-7.4, 0.4)

-0.2

(-1.4, 1.1)

4.9 %

High sugar

-3.0*

(-3.7, -2.3)

0.0

(-0.4, 0.4)

-3.7

(-7.5, 0.2)

0.0

(-1.1, 1.1)

0.1 %

High Fat

-1.3*

(-1.6, -1.0)

0.1

(-0.9, 1.1)

-3.6

(-7.5, 0.4)

-0.1

(-1.4, 1.2)

3.0 %

High sodium

-0.2*

(-0.3, 0.0)

0.4

(-1.5, 2.3)

-3.6

(-7.3, 0.1)

-0.1

(-0.4, 0.3)

1.7 %

  1. 1Analyses adjusted for child’s sex and age, mother’s education level, marital state, home ownership, and day of recall
  2. 2 Expressed in minutes of advertising per week (a-coefficient reflects policy effect on advertising)
  3. 3 Total effect of policy on consumption of “high-in” products in kcal = -53 kcal [99CI: -147, 41] p = 0.146
  4. 4 Total effect of policy on energy adjusted consumption of high-in products = -3.7 % kcal [99CI: -7.4, 0.0] p = 0.011
  5. 5 ab/[(ab) + c’] *100
  6. *p < 0.01.